Paritian

Electricity

Maximum Power Transfer Calculator (Load Matching)

Power, voltage, current and efficiency in a load fed from a source with internal resistance, and how close that load comes to the most the source could ever deliver.

Results

Power in the load 8.000 W
Efficiency (share of the power that reaches the load) 66.7 %
Voltage across the load 8.000 V
Current through the load 1.000 A
Most power this source can ever deliver (load = source resistance) 9.000 W
Load power as a share of that maximum 88.9 %
How it changes
Power in the loadLoad resistance 0.0 – 16.0. Power in the load: 0 → 5.76; Most power this source can ever deliver (load = source resistance): 9 → 9Power in the loadMost power this source can ever deliver (load = source resistance)02468100.05.010.015.0Load resistance (Ω)

The dashed line marks the value you entered.

What this tool does

A source with internal resistance gives its largest power to a load whose resistance equals its own — and at that point exactly half of the power is wasted inside the source, so efficiency is only 50 %. That is the right trade for a radio signal or a speaker driven from a weak source, where power at the load matters; it is the wrong one for a battery or a mains supply, where you want a load much larger than the source resistance so that the losses stay small. The chart shows how flat the peak is: the load can be off by a factor of two and still get about 89 % of the maximum.

Formula

P_load = V² R_L ÷ (R_S + R_L)² · maximum when R_L = R_S: P_max = V² ÷ 4R_S · efficiency = R_L ÷ (R_S + R_L)

Variables

SymbolMeaningUnit
vsSource voltage (open circuit)V
rsSource (internal) resistanceΩ
rlLoad resistanceΩ
PLPower in the loadW
EFEfficiency (share of the power that reaches the load)%
VLVoltage across the loadV
ILCurrent through the loadA
PMMost power this source can ever deliver (load = source resistance)W
PCLoad power as a share of that maximum%

Worked example

  • Source voltage (open circuit)12 V
  • Source (internal) resistance4 Ω
  • Load resistance8 Ω
  • Power in the load8.000 W
  • Efficiency (share of the power that reaches the load)66.7 %
  • Voltage across the load8.000 V
  • Current through the load1.000 A
  • Most power this source can ever deliver (load = source resistance)9.000 W
  • Load power as a share of that maximum88.9 %

Limitations

  • The formula assumes ideal conditions: no friction losses, no air resistance and no efficiency losses unless you enter them.
  • Mixing units is the most common source of error. Convert every input to the units shown next to each field before calculating.