Paritian

Heat & Fluids

Mixing Temperature Calculator (Final Temperature of Two Substances)

The temperature two amounts of water, or any two substances, settle at when mixed or put in contact, and the heat that moves between them.

Results

Final temperature of the mixture 44.00 °C
Heat passed from the hotter to the colder 301.39 kJ
Temperature change of the first substance -36.00 °C
Temperature change of the second substance 24.00 °C
How it changes
Final temperature of the mixtureMass of the second substance 0.0 – 10.0. Final temperature of the mixture: 80 → 30Final temperature of the mixture0204060800.02.04.06.08.010.0Mass of the second substance (kg)

The dashed line marks the value you entered.

What this tool does

When two things at different temperatures meet and nothing escapes to the surroundings, the heat one loses is exactly the heat the other gains, which gives T = (m₁c₁T₁ + m₂c₂T₂) ÷ (m₁c₁ + m₂c₂): an average weighted by heat capacity m × c. Water's specific heat is large — about 4186 J/(kg·K) against about 900 for aluminium and about 385 for copper — which is why a hot piece of metal barely warms a bucket of water. The result holds only if nothing melts, freezes or boils on the way (melting ice absorbs about 334 kJ/kg at 0 °C) and ignores heat lost to the container and the air.

Formula

T_final = (m₁ c₁ T₁ + m₂ c₂ T₂) ÷ (m₁ c₁ + m₂ c₂)

Variables

SymbolMeaningUnit
m1Mass of the first substancekg
c1Specific heat of the first substance (water 4186)J/(kg·K)
t1First temperature°C
m2Mass of the second substancekg
c2Specific heat of the second substance (water 4186)J/(kg·K)
t2Second temperature°C
TFFinal temperature of the mixture°C
QHeat passed from the hotter to the colderkJ
D1Temperature change of the first substance°C
D2Temperature change of the second substance°C

Worked example

  • Mass of the first substance2 kg
  • Specific heat of the first substance (water 4186)4186 J/(kg·K)
  • First temperature80 °C
  • Mass of the second substance3 kg
  • Specific heat of the second substance (water 4186)4186 J/(kg·K)
  • Second temperature20 °C
  • Final temperature of the mixture44.00 °C
  • Heat passed from the hotter to the colder301.39 kJ
  • Temperature change of the first substance-36.00 °C
  • Temperature change of the second substance24.00 °C

Limitations

  • The formula assumes ideal conditions: no friction losses, no air resistance and no efficiency losses unless you enter them.
  • Mixing units is the most common source of error. Convert every input to the units shown next to each field before calculating.