Paritian

Physics

Compton Scattering Calculator

Energy and wavelength of a photon after bouncing off an electron, the energy the electron takes, and the Compton edge and backscatter peak of a gamma line.

Results

Energy of the scattered photon 288.39 keV
Energy given to the electron 373.61 keV
Wavelength shift 2.4263 pm
Wavelength of the incoming photon 1.8729 pm
Compton edge (most the electron can get) 477.65 keV
Backscatter peak (photon at 180°) 184.35 keV
How it changes
Energy of the scattered photonScattering angle 0 – 180. Energy of the scattered photon: 662 → 184.35; Energy given to the electron: 0 → 477.65Energy of the scattered photonEnergy given to the electron0200400600800050100150Scattering angle (°)

The dashed line marks the value you entered.

What this tool does

Arthur Compton's 1923 experiment showed X-rays bouncing off electrons as if they were particles: the scattered photon comes out with less energy, and the loss depends only on the angle. The wavelength shift can never exceed twice the Compton wavelength, about 4.85 pm, so it is invisible for light but large for gamma rays. That is where the Compton edge and the backscatter peak in a gamma spectrum come from — for the 662 keV line of caesium-137 they sit near 478 keV and 184 keV. The formula assumes a free electron at rest.

Formula

Δλ = (h ÷ mₑc)(1 − cos θ) · E′ = E ÷ (1 + (E ÷ mₑc²)(1 − cos θ)), mₑc² = 510.999 keV

Variables

SymbolMeaningUnit
enPhoton energykeV
thScattering angle°
EPEnergy of the scattered photonkeV
KEEnergy given to the electronkeV
DLWavelength shiftpm
W0Wavelength of the incoming photonpm
CECompton edge (most the electron can get)keV
BSBackscatter peak (photon at 180°)keV

Worked example

  • Photon energy662 keV
  • Scattering angle90 °
  • Energy of the scattered photon288.39 keV
  • Energy given to the electron373.61 keV
  • Wavelength shift2.4263 pm
  • Wavelength of the incoming photon1.8729 pm
  • Compton edge (most the electron can get)477.65 keV
  • Backscatter peak (photon at 180°)184.35 keV

Limitations

  • The formula assumes ideal conditions: no friction losses, no air resistance and no efficiency losses unless you enter them.
  • Mixing units is the most common source of error. Convert every input to the units shown next to each field before calculating.