Paritian

Electricity

RL Circuit Calculator (Inductor Current and Time Constant)

Current in a coil a given time after a voltage is switched on, the final current, the time constant L ÷ R and the energy stored in the magnetic field.

Results

Current at that time 0.472 A
Final current (steady state) 1.200 A
Time constant 10.00 ms
Share of the final current reached 39.3 %
Energy stored in the coil at that time 11.147 mJ
Time to reach 99 % of the final current 46.05 ms
How it changes
Current at that timeTime 0.0 – 50.0. Current at that time: 0 → 1.19191Current at that time00.511.50.010.020.030.040.050.0Time (ms)

The dashed line marks the value you entered.

What this tool does

An inductor opposes a sudden change of current, so when a voltage is applied across a coil and a resistor the current climbs along an exponential curve instead of jumping: it reaches 63 % of its final value V ÷ R after one time constant τ = L ÷ R and about 99 % after 4.6 τ. The energy kept in the field is ½·L·i². That energy has nowhere to go when the switch opens, which is why relay coils and motors need a flyback diode — otherwise the collapsing field makes a voltage spike many times the supply.

Formula

τ = L ÷ R · i(t) = (V ÷ R) × (1 − e^(−t ÷ τ)) · E = ½ L i²

Variables

SymbolMeaningUnit
vVoltageV
rResistanceΩ
lInductance of the coilmH
tTimems
ITCurrent at that timeA
IMFinal current (steady state)A
TATime constantms
PCShare of the final current reached%
ENEnergy stored in the coil at that timemJ
T9Time to reach 99 % of the final currentms

Worked example

  • Voltage12 V
  • Resistance10 Ω
  • Inductance of the coil100 mH
  • Time5 ms
  • Current at that time0.472 A
  • Final current (steady state)1.200 A
  • Time constant10.00 ms
  • Share of the final current reached39.3 %
  • Energy stored in the coil at that time11.147 mJ
  • Time to reach 99 % of the final current46.05 ms

Limitations

  • Electrical installations are governed by national wiring rules. Cable sizing also depends on installation method, grouping, ambient temperature and protection devices, which this calculator does not evaluate.
  • The formula assumes ideal conditions: no friction losses, no air resistance and no efficiency losses unless you enter them.